Dope Tech Episode 2

<<@veritasium says : A number of people are asking why this problem is “dangerous”. It’s described as dangerous because its difficulty has defeated the world’s greatest mathematical minds for generations. Paul Erdos, a famous mathematician, said, "Mathematics is not yet ripe enough for such questions." Jeffrey Lagarias called it "an extraordinarily difficult problem, completely out of reach of present day mathematics". The problem is so maddeningly difficult, mathematicians are warned to stay away from it. Watch the full video for more context: https://www.youtube.com/watch?v=094y1Z2wpJg>> <<@cemkarci7452 says : Its so easy>> <<@adamgrimsley2900 says : Oh well, that's fine.>> <<@justincider8892 says : Dangerous? How?>> <<@flowerpower2384 says : So when playing with these 2 rules on all the numbers from 1 to 9 we end up in the loop. That's actually a nice play with numbers. And I would even think it's possible that when we change the rules (like x4-1) and play the game long enough it will always end up in a loop... Did someone try this already? But for me it's no problem but an interesting observation... What kind of program actually works with these rules?🤔>> <<@Espadacortadecobre says : but... i didnt choose 7>> <<@AnaMayee_ says : I was still deciding to choose a number when he popped up saying "7, good choice" 😭>> <<@_InTheBin says : Instructions unclear. Chose 1 from the start, got stuck in loop immediately and am still looping ♻️>> <<@SerLagsalot says : What's so difficult? So it winds up in a repeating pattern if a set of consistent rules is applied. That's just the way it works. It's not like there's some kind of hidden mystery to the working of math that could change the outcome within the given rule set.>> <<@hamzaberber8700 says : Birde şu sayıyı deneyin bakalım :1,19>> <<@Dimitris-wk2ge says : Do you know what dangerous actually means.?>> <<@Rishi-p6m8m says : Thala For a reason🙌>> <<@exponential_e says : “Pick a number, 7…” Bro. How did you know?>> <<@dirtwizard5647 says : And here I thought 420 was dangerous ❤😂>> <<@ArchieWatt-v8d says : it is called 3n+1 me and my friend did it for weeks and got got the same last numbers>> <<@SteffedPepper says : So I'm probably wrong here. And i read the pinned message about why it is "dangerous". But my question is .. is it even a "problem"? You're just following 2 rules. And it gets stuck in a loop. Is there anything to solve? It seems to math correctly and you're not looking for a solution>> <<@Orudaiken says : The answer was just as simple as the last time I answered. 11 and beyond don't exist. Only 1 to 10. 2,4,6,8,and 10 are all decreasing numbers. 1 becomes 4, 3 becomes 10, 5 becomes 6, 7 becomes 2, and 9 becomes 8. So half the numbers from 0 to 10 decrease, and the other half goes up, before going down. BUT, 2 becomes 1, 4 becomes 2, 6 becomes 3, 8 becomes 4, and 10 becomes 5. Tallied up there are 5 downs and 5 ups for odd integers. And 7 downs and 3 ups for positive intergers. Given that the number decreases more than it increases it will approach 1 at infinity.>> <<@BalaMurugan-ps4rt says : I am more suprised that he guessed my number 💀💀💀💀>> <<@Aryan-y8o3h says : Proof: by applying this rule to check each number goes from 1 to 10 , it is found that every number ends in the 4-2-1 loop. And for every positive integer eventually fall in this 1 to 10 numbers zone . Hence the all positive integers end up in 4-2-1 loop.>> <<@WestonRosch says : Well, this almost gave me an anxiety attack>> <<@amore7_7 says : 4+2+1=7............>> <<@spaceguy20_12 says : 9 odd 9x3=27 27+1=28 28 even 28/2=14 14 even 14/2=7 7 odd 7x3=21 21+1=22 22 even 22/2=11 11 odd 11x3=33 33+1=34 34 even 34/2=17 17 odd 17x3=51 51+1=52 52 even 52/2=26 26 even 26/2=13 13 odd 13x3=39 39+1=40 40 even 40/2=20 20 even 20/2=10 1 even 10/2=5 5 odd 5x3=15 15+1=16 16 even 16/2=8 8 even 8/2=4 4 even 4/2=2 2 even 2/2=1 1 odd 1x3=3 3+1=4 Go back to “4 even”>> <<@Elvcjd says : Isn’t 28 like an infinity loop>> <<@brianmalik9383 says : So?>> <<@jablonicusdemarco6213 says : Normally I always pick 7, he picked seven. So I picked 4..... I technically entered the loop from the start. So I have the shortest infinite path... Beautiful>> <<@marwan4education40 says : Yeah where's the problem We can make another one by other operations and also may it can work for all postive number ( i mean R+)>> <<@UlikbuNam-q2d says : Okay, but what’s the point? I understand I can’t comprehend the magnitude of my question, but it sounds to me like we have our answer; you take a positive integer, apply these two rules and this is the result. What is there left to solve?>> <<@Undisputed-hl1ee says : Now a simple question, what is the purpose of this question? 🤔>> <<@oov55 says : Thank You for wasting my time for 3 minutes -- but that's the internet, I guess.>> <<@monishsatwani_ says : This is so scary. I can’t sleep now.>> <<@mskoliwadmsk3775 says : 7 Thala from r a reason>> <<@daffodilia says : pickanumberseven? goodchoice>> <<@martinmassera says : Seems like a random problem. What would be the benefit of solving this?>> <<@DanielSiemek says : Please tell me why this isnt the most pointless video I've ever seen?>> <<@WarrenSaint154 says : Don’t let Terrence Howard see this>> <<@royroy333 says : i dont understand why this is a problem... its just a sort of constitutionality isn't it? what if we apply another rule that says that whenever we reach this sort of loop - we change the rule in a orderly ashion, like - from this numer on we apply (x5+1) to every odd number. Actually i just tried it - and the got lost... :-) Wonder what kind of conjecture we'll get if we try to x this formula by every prime number till, say, 101.>> <<@Touyube23 says : Something like 4.7 solves the dangerousness of it>> <<@real_baum_hz4706 says : As a programmer i have to say, where's the problem? Does it return null? Does it not stay in the loop from one point? I mean you make 2 calculations an infinite amount of times and wonder you eventually catch a number equal to 2^x and devide every even number by 2. (Sorry for bad english, ask me again if you did'nt understand somethin)>> <<@sarthaktyagu says : can we use 10-adic no. :- .........333333333 ?>> <<@FullFull-uy5eh says : Loopjknooiml>> <<@FullFull-uy5eh says : Mean>> <<@AngelSchleicher-t1t says : I agree>> <<@martynasmartynas4403 says : He said 7 due to the seven-blue theorem>> <<@AyanGhosh-ti8bm says : WHY!!!!!!>> <<@AmanSeep-xq3ig says : Thala for a reason 😊>> <<@Axion97Player says : This problem is dangerous because no one knows how to prove whether the statement "any positive integer will eventually end up in that loop" is true or not. Maybe it is, maybe it isn't, no one can prove it is or it isn't.>> <<@TheCondorGalaxy says : Why Is It Dangerous?>> <<@NourRabayah says : I chose 0.5>> <<@coder-x7440 says : It’s not a problem, it’s nature revealed through math. Formalism without a hypothesis. Terrance Tao was able to prove it has no solution up to a nearly unreachable extent, with no indication it’s falsifiable. To me, the pattern in demonstrates is that of causality itself and explains why nature always seeks equilibrium.>> <<@Ymir._ says : That conjecture is likely true, but I'd like to pose a different question. The question is, what is the general trend of the number of steps required based on the size of the number.>>