Dope Tech Episode 2

<<@nguyendo228 says : I think like u open a box and if u get a number like57 u take 57th one and continue it>> <<@BlinkLiliesQueen says : This is oen of the TED-ED riddles>> <<@jitadityaghosh-n6d says : EASY THE 1ST PRISONER 1ST LOOKS AT THE NO OF BOX HE HAS HIMSELF,THEN TO THE NUMBER HE FINDS IN THE BOX AND CONTINUE LIKE THIS 50 TIMES.>> <<@seanpeterdawsob says : Please can you do a video on this > “Everyone on earth takes a private vote by pressing a red or blue button. If more than 50% of people press the blue button, everyone survives. If less than 50% of people press the blue button, only people who pressed the red button survive. Which button would you press? BE HONEST.”>> <<@shwethakanth says : I would like to suggest but they are certain conditions of mine (1) There are no Security Cameras inside the room (2)There should be no checking after a prisoner had got his number. (3)Every prisoner should have a small blade with them My stategy is the following The first prisoner should go and make hole in each 1 to 10 boxes and see if his number is there not there ok, Next, go to 100 to 90 boxes same process not there fine, next 40 to 50 boxes not there fine next 20 to 30 boxes there will be a high chance of obtaining his number but he must be careful not to open the boxes after making the hole and if he gets his number in the first shot he should do the hole to another 49 boxes ok after his job and obtaining his number The second prisoner comes he should find out which boxes have holes in them if he finds his number in those boxes but he should wait and make a hole in the next 50 boxes and fond his number if he has found and go The next prisoners should look in all the boxes without opening them can they find their numbers and be freed for the common good.>> <<@AyonaDeDe says : This reminds me of that ted -ed riddle where the manager of your music band kept all your instruments in sealed boxes; with the picture of the an instrument on the box. The strategy you as a drummer came up with was to go to your box first and remove that instrument and then go to the box with the instrument on it . And you will find it eventually>> <<@თამარხურციძე-შ2ფ says : 1to50and its 50precent>> <<@JaredBarreto-z1u says : If the box is your power, what are you without it?>> <<@QueenLouisaUltimate says : We saw that 67>> <<@atulnarkhede4846 says : Can you do an episode on hydraulic goods lift. Also, how to fix the level matching issues on one of those, if you could suggest a solution.>> <<@Sammi-m1g says : They leave it EXACTLY as they FOUND it, which means if the first 1 finds theirs and LEAVES IT as he FOUND IT there would be 50 boxes lifted and if the 2nd guy's number isn't one of the opened boxes he can open the other 50 and everyone else's numbers would be available right there, and even if the 2nd guy's number is there he can still open 49 and take his, leaving just one box for the 3rd guy to open and if it's his he takes it and if it isn't he looks at the open ones and takes it, so then the chances of them being free are now 50, and it's not breaking the rules.>> <<@rusticb2850 says : How do you choose the next box if your first loop is nested below 50?>> <<@meghanasaid7060 says : Their best strategy is to lie>> <<@Buhjiner says : Your variables and questions suck! Humans do NOT match math problems meaning a variable as in them strategizing is meaningless. We don’t have the same memory of the plan and we don’t all act the same as is listening to the plan and following through, 3…. Nerves. You cannot count them in but it fucks with the outcome. Therefore these questions are so off base it’s just for reference purposes. There is no mathematic argument. It’s different everytime. Why all you math people stretch the truth to match your argument is hysterical! Cherry picking at its finest. Math doesnt make you smarter. It gives you structure and patience. Oh and a head so big it’s funny how dumb yall become. Focusing sheer attention on factual numbers and outcomes but adding life to them cannot happen. So please be smarter and change your approaches and make better arguments. Just because you guys make it harder and harder doesn’t make you smarter and smarter. You end up losing abilities if perspective and therefore become less relevant and purposed.>> <<@Buhjiner says : Factually impossible to find the same grain of sand. It would never happen. But you seem to have really vague and dumb variables in your questions, like the strategy aspect? Null. It wouldn’t ever matter. They do what humans do and forget or stray away.>> <<@CullenSoden says : Cant you make sure they all get their numbers if you’re odd only pick odd numbered boxes and if you’re even only pick even numbered boxes>> <<@M.Twilight says : If seen a very similar riddle on the Ted ed channel, and Panthers1521 (and maybe others that I might have missed) has the right idea. You first open the box with your number and keep going in this sequence until you find the box for you.>> <<@eggo848 says : Finding the 9th multiple of their number.>> <<@ksjtalents769 says : There is actually a very better way to do this lets take an example Step 1 - Start with YOUR number box Prisoner #7 opens Box 7 first. Step 2 - Follow the treasure map Inside Box 7 is a slip saying "43". Now open Box 43. Inside Box 43 is a slip saying "19". Now open Box 19. Keep following the numbers like a treasure hunt. Step 3 - You'll eventually find yourself Eventually, you'll open a box containing slip "7" → Success! lot of u might wonder why this needs to work i hav an explanation for that also The random shuffle creates chains/loops: Example Chain: 7 → 43 → 19 → 82 → 7 (back to start) This is a 4-box loop. Important Fact: If you start at your own number box, you're guaranteed to be on the loop containing your slip. ✅ When They Win: They ALL win if NO loop is longer than 50 boxes. Why? Because if your slip is in a loop of length 30, you'll find it in exactly 30 tries (following the chain). But if your slip is in a loop of length 75, you'd need 75 tries → but you're limited to 50 → you fail. THE MATH With 100 boxes: About 31% of shuffles have all loops 50 or shorter About 69% have at least one loop longer than 50 So: Random guessing → 0.000...% chance Chain strategy → 31% chance>> <<@Silvio-gk says : Why is the first box opened 67??>> <<@AHMAD-HABIBULLAH says : guys did u realize the first prisoner open the and the number is 67>> <<@tyediednightmare says : Rules to win this game is so easy that everyone would only need to go once 1. Everyone goes in and opens their box so 50 opens box number 50 then leaves the room after everyone did they will line up by witch number they found in the box not their number so if 50 found 1 he would be the first in line and boom everyone know witch box their number is in without checking all 50 boxes each and with zero communication>> <<@andres93b says : Welcome to algorithmic thinking. Great video>> <<@WasteOfTime_WR says : Can someone explain how the strategy would reach 30% with 2 prisoners? In my mindestens with each opening 1 box, they would a have 25% chance to both pick right>> <<@JohnRustyLola says : I was thinking if there is one number that intentionally place it with 51 steps... Is that cheating? Let say there is a number that correspond with the box number ... for example 20+ boxes.. does the solution still solve this riddle?>> <<@Goblin-f5p says : Bro i think i get it. If the prisoners are rounded up and killed instantly after one doesnt find his number then if the first guy enters and chooses boxes 1-50 and everyone is alive, it means he found it. So the next guy goes and chooses 50-100 so that he has a higher chance. AND THEN THE NEXT GUY HAS A 50% CHANCE AND THEN THE NEXT GUY HAS A HIGHER CHANCE. I didnt do the maths but MAYBE that goes to a third. so like 50/100 then 50/99 and then 50/98 and then 50/96? I might be so wrong bro edit: im onto nothing>> <<@William_1347 says : Someone needs to get 100 numbered boxes with pieces of paper and verify this.>> <<@johnt6806 says : A very interesting corollary is what the probability is that the very first prisoner is able to tell everyone else that they will all live. It comes down to whether the first prisoner is in a box cycle of exactly 50. If they are, then they know that everyone else in that cycle will also find their number, and any other cycles cannot be longer than 50 because there are only 50 numbers remaining that aren't in that first cycle.>> <<@juanignaciohercemoreno6933 says : Wow first crate number 1 opened is 67>> <<@SouthwestClassicInspections says : If there are 100 boxes and you get to open 50 of them, have everyone just keep opening the same 50 boxes it becomes a 50-50 but you get 100 shots at it. I’m not a mathematician so I don’t know the numbers on it.>> <<@ashrafMoFathy says : 1- first half opens from 1 to 50 2- second half opens from 51 to 100 Easy and simple>> <<@fionamayfield4762 says : You know when the internet is messed up when I saw the first box open it said "67">> <<@LazyCrazy-p4t3s says : Open the box that has your number. for example, If you're the first prisoner open the box with a number one and what number is in there you must open it. For example you opened the box 1 and it has the number 56 then, open the number 56 and so on i learned this from TedEd>> <<@cam-unc says : Who looked for 67>> <<@billyclark6062 says : The answer is... they have a better chance of making it out, more than your videos having answers at the end 😅>> <<@jiezhang5812 says : number 1 goes to box 1.whatever number is in that will look in box number # and on ans on and on.>> <<@SpaceNoutilus says : Bro opens 67 room😂😂😂😂😂>> <<@kroos_07 says : @Veritasium Before Thinking about my method, take a screenshot given in the videos with the order number 1 to 100 And it's number in. Then get started:- The prisoner labeled each numbers going in the room . He must open their own number 1st then he check the number in it after that he goes for the number in that 1st opend box, open the box see the num-> go for that labeled num & open the box then see ..... after repeating this method everyone will find their own number within 50 chances. I tried I found it every number ❤😊>> <<@Electronicfort says : Screw that, I’m grabbing a clipboard for the gang, and we communicate to it, not each other. Jotting down numbers and their box without breaking any rules.>> <<@loveordevotion says : > see if you have green eyes > ask to leave>> <<@Zivojin168 says : 67🎉🎉🎉🎉🎉🎉>> <<@severalmileshighclub says : Oh my God the first box opened has 67 in it>> <<@Momthemum says : Each prisoner could take their number during their turn. No communicating and the room wouldn’t change because the numbers are boxed.>> <<@peterrisley24 says : Is the AUTHOR of this video a Nobel prize winner in physics>> <<@Economivision says : I’m going to guess the strategy without seeing the video, but I would say that a prisoner could take their number from their box, then swap the entire box with the box in the first spot… then each succeeding prisoner do exact this in the order that they don their number. This way each turn successively increases their odds in the next iteration as compared with the last. By the 100th prisoner, he’s got like 100% chance of getting his box.>> <<@Crating says : Do they have to leave 1 at a time?>> <<@Erth-a-n-gle says : Answer: You have to cheat- timestamp @104 1153 Aquarius libra Gemini Port. Ro. Ad 322 18. 🚒>> <<@materialdusty says : Prevention of executions not a game to be playing life or death Slaves must be freed a chance at real life not just surviveing not just stuck in a metal box>> <<@andrijastankovic6004 says : Mr who watched simmilar ted ed riddle but with 10 musicians: "I am 4 paralel universes ahead of you">> <<@xhibitmusic says : Trying to get people to look up for keywords you rank for is genius!>>